DILR Test 3 Practice
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Detailed Analysis:
On the basis of the given information we can make the following table.
|
Ladies |
Suburbs |
Occupations |
|
Mrs. Bhakti |
Andheri |
Bank Employee |
|
Mrs. Preeti |
Mumbai |
Guide |
|
Mrs. Neeti |
Borivli |
Shop Owner |
|
Mrs. Shanti |
Dadar |
Teacher |
|
Mrs. Rati |
Kurla |
Actress |
Detailed Analysis:
On the basis of the given information we can make the following table.
|
Ladies |
Suburbs |
Occupations |
|
Mrs. Bhakti |
Andheri |
Bank Employee |
|
Mrs. Preeti |
Mumbai |
Guide |
|
Mrs. Neeti |
Borivli |
Shop Owner |
|
Mrs. Shanti |
Dadar |
Teacher |
|
Mrs. Rati |
Kurla |
Actress |
Detailed Analysis:
On the basis of the given information we can make the following table.
|
Ladies |
Suburbs |
Occupations |
|
Mrs. Bhakti |
Andheri |
Bank Employee |
|
Mrs. Preeti |
Mumbai |
Guide |
|
Mrs. Neeti |
Borivli |
Shop Owner |
|
Mrs. Shanti |
Dadar |
Teacher |
|
Mrs. Rati |
Kurla |
Actress |
Detailed Analysis:
On the basis of the given information we can make the following table.
|
Ladies |
Suburbs |
Occupations |
|
Mrs. Bhakti |
Andheri |
Bank Employee |
|
Mrs. Preeti |
Mumbai |
Guide |
|
Mrs. Neeti |
Borivli |
Shop Owner |
|
Mrs. Shanti |
Dadar |
Teacher |
|
Mrs. Rati |
Kurla |
Actress |
Detailed Analysis:
On the basis of the given information we can make the following table.
|
Ladies |
Suburbs |
Occupations |
|
Mrs. Bhakti |
Andheri |
Bank Employee |
|
Mrs. Preeti |
Mumbai |
Guide |
|
Mrs. Neeti |
Borivli |
Shop Owner |
|
Mrs. Shanti |
Dadar |
Teacher |
|
Mrs. Rati |
Kurla |
Actress |
Detailed Analysis:
Ten students are Alex(A), Bryan(B), Charlie (C), Derek(0), Elwin(E), Frank(F), George(G), Harish(H), lan(I) and Joseph(J). D, H and J are from three different colleges. Also, two of B, E and 6 are from Harvard.
Therefore, there are at least 3 students from Harvard. If one of F or A is from Harvard, then two of the colleges will have the same number of participants.
Thus, neither F nor A is from Harvard. Also, it implies that most number of participants are from Harvard and there are at least two participants from each college. Thus, the only possibility is that there are 5 students from Harvard, and 3 and 2 students horn Stamford and Oxford (in any order).
From condition (v), Derek and Alex are from Oxford and Frank is from Stanford.
Thus, partial information about students is as below:
|
Harvard (5) |
Stanford |
Oxford |
|
J |
H |
D |
|
C |
F |
A |
|
I |
Two of B, E and G from Harvard.
As it can be seen from the table above, Ian and Derek are from different colleges. Hence, [3].
Detailed Analysis:
Ten students are Alex(A), Bryan(B), Charlie (C), Derek(0), Elwin(E), Frank(F), George(G), Harish(H), lan(I) and Joseph(J). D, H and J are from three different colleges. Also, two of B, E and 6 are from Harvard.
Therefore, there are at least 3 students from Harvard. If one of F or A is from Harvard, then two of the colleges will have the same number of participants.
Thus, neither F nor A is from Harvard. Also, it implies that most number of participants are from Harvard and there are at least two participants from each college. Thus, the only possibility is that there are 5 students from Harvard, and 3 and 2 students horn Stamford and Oxford (in any order).
From condition (v), Derek and Alex are from Oxford and Frank is from Stanford.
Thus, partial information about students is as below:
|
Harvard (5) |
Stanford |
Oxford |
|
J |
H |
D |
|
C |
F |
A |
|
I |
Two of B, E and G from Harvard.
Joseph cannot be from a college where the least number of participants are. Hence, [2].
Detailed Analysis:
Ten students are Alex(A), Bryan(B), Charlie (C), Derek(0), Elwin(E), Frank(F), George(G), Harish(H), lan(I) and Joseph(J). D, H and J are from three different colleges. Also, two of B, E and 6 are from Harvard.
Therefore, there are at least 3 students from Harvard. If one of F or A is from Harvard, then two of the colleges will have the same number of participants.
Thus, neither F nor A is from Harvard. Also, it implies that most number of participants are from Harvard and there are at least two participants from each college. Thus, the only possibility is that there are 5 students from Harvard, and 3 and 2 students horn Stamford and Oxford (in any order).
From condition (v), Derek and Alex are from Oxford and Frank is from Stanford.
Thus, partial information about students is as below:
|
Harvard (5) |
Stanford |
Oxford |
|
J |
H |
D |
|
C |
F |
A |
|
I |
Two of B, E and G from Harvard.
From the given condition, George and Elwin are from Harvard. Thus, Elwin and Ian are from the same college. Hence, [3].
Detailed Analysis:
Ten students are Alex(A), Bryan(B), Charlie (C), Derek(0), Elwin(E), Frank(F), George(G), Harish(H), lan(I) and Joseph(J). D, H and J are from three different colleges. Also, two of B, E and 6 are from Harvard.
Therefore, there are at least 3 students from Harvard. If one of F or A is from Harvard, then two of the colleges will have the same number of participants.
Thus, neither F nor A is from Harvard. Also, it implies that most number of participants are from Harvard and there are at least two participants from each college. Thus, the only possibility is that there are 5 students from Harvard, and 3 and 2 students horn Stamford and Oxford (in any order).
From condition (v), Derek and Alex are from Oxford and Frank is from Stanford.
Thus, partial information about students is as below:
|
Harvard (5) |
Stanford |
Oxford |
|
J |
H |
D |
|
C |
F |
A |
|
I |
Two of B, E and G from Harvard.
The colleges of 7 students out of 10 can be definitely determined. Therefore, the required answer is 7.
Detailed Analysis:
The pattern is each number is obtained by multiplying the previous number by 2. Therefore, the next number in the sequence is 48 * 2 = 96. So, the correct answer is option 1) 96.