DILR Test 5 Practice
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Detailed Analysis:
In this series, the difference between consecutive terms increases by 3 each time. The differences between the terms are: 5 - 2 = 3, 10 - 5 = 5, 17 - 10 = 7. So, the next difference should be 9. Adding 9 to the last term, we get: 17 + 9 = 26.
Therefore, the next term in the series is 26.
Detailed Analysis:
Given 'peacock is designated as the national bird of India' is coded as ' 5688999 35 1135556678 56 458 13666689 1334 79 13366'
9 is the code for o and c from the words peacock and of.
F is coded as 7 from the word of.
I is coded as either 3 or 6 from the word India, but from the word 'is' and 'designated' code for 'I' is 3.
S is coded as 5 from the word is.
A is coded as 6 from the word 'as'.
N is coded as 6 from the word national.
Thus D is coded as 1 from the word India.
E is coded as 5 from the word designated.
T is coded as 8 from the word 'the' and 'National'.
Thus H is coded as 4 from the word 'the'. G is coded as 7. L is coded as 1 from the word 'National'.
P and K are coded as 8 from the word 'peacock'. B and R are coded as 3 and 4 many order from the word 'bird'.
We get the codes as follows
. 
B and R is coded as 3 or 4.
Detailed Analysis:
Given 'peacock is designated as the national bird of India' is coded as ' 5688999 35 1135556678 56 458 13666689 1334 79 13366'
9 is the code for o and c from the words peacock and of.
F is coded as 7 from the word of.
I is coded as either 3 or 6 from the word India, but from the word 'is' and 'designated' code for 'I' is 3.
S is coded as 5 from the word is.
A is coded as 6 from the word 'as'.
N is coded as 6 from the word national.
Thus D is coded as 1 from the word India.
E is coded as 5 from the word designated.
T is coded as 8 from the word 'the' and 'National'.
Thus H is coded as 4 from the word 'the'. G is coded as 7. L is coded as 1 from the word 'National'.
P and K are coded as 8 from the word 'peacock'. B and R are coded as 3 and 4 many order from the word 'bird'.
We get the codes as follows
. 
B and R is coded as 3 or 4.
Detailed Analysis:
Given 'peacock is designated as the national bird of India' is coded as ' 5688999 35 1135556678 56 458 13666689 1334 79 13366'
9 is the code for o and c from the words peacock and of.
F is coded as 7 from the word of.
I is coded as either 3 or 6 from the word India, but from the word 'is' and 'designated' code for 'I' is 3.
S is coded as 5 from the word is.
A is coded as 6 from the word 'as'.
N is coded as 6 from the word national.
Thus D is coded as 1 from the word India.
E is coded as 5 from the word designated.
T is coded as 8 from the word 'the' and 'National'.
Thus H is coded as 4 from the word 'the'. G is coded as 7. L is coded as 1 from the word 'National'.
P and K are coded as 8 from the word 'peacock'. B and R are coded as 3 and 4 many order from the word 'bird'.
We get the codes as follows
. 
B and R is coded as 3 or 4.
Detailed Analysis:
Given 'peacock is designated as the national bird of India' is coded as ' 5688999 35 1135556678 56 458 13666689 1334 79 13366'
9 is the code for o and c from the words peacock and of.
F is coded as 7 from the word of.
I is coded as either 3 or 6 from the word India, but from the word 'is' and 'designated' code for 'I' is 3.
S is coded as 5 from the word is.
A is coded as 6 from the word 'as'.
N is coded as 6 from the word national.
Thus D is coded as 1 from the word India.
E is coded as 5 from the word designated.
T is coded as 8 from the word 'the' and 'National'.
Thus H is coded as 4 from the word 'the'. G is coded as 7. L is coded as 1 from the word 'National'.
P and K are coded as 8 from the word 'peacock'. B and R are coded as 3 and 4 many order from the word 'bird'.
We get the codes as follows
. 
B and R is coded as 3 or 4.
Detailed Analysis:
Let the present age of Ram = x years. The present age of his son = y years. The present age of Ram's father = z years. By the question, x + z = 100 x = 100 - z ...(i)
Again, z = 5y ...(ii)
and y + (z - x) = x + 8 y + z = 2x + 8.
Putting the value of x from equation (i) we get,
y + z = 2 (100 - z) + 8 y + 3z = 208. Putting the value of z from equation (ii) we get,
y + 3(5y) = 208 = 16y = 208. y = 13, from equation (ii), z = 65 and from (i) x = 35.
Age of son = 13 years. Ans.(2)
Detailed Analysis:
Let the present age of Ram = x years. The present age of his son = y years. The present age of Ram's father = z years. By the question, x + z = 100 x = 100 - z ...(i)
Again, z = 5y ...(ii)
and y + (z - x) = x + 8 y + z = 2x + 8.
Putting the value of x from equation (i) we get,
y + z = 2 (100 - z) + 8 y + 3z = 208. Putting the value of z from equation (ii) we get,
y + 3(5y) = 208 = 16y = 208. y = 13, from equation (ii), z = 65 and from (i) x = 35.
Age of Ram 5 years ago = 35 - 5 = 30 years. Ans.(1)
Detailed Analysis:
Let the present age of Ram = x years. The present age of his son = y years. The present age of Ram's father = z years. By the question, x + z = 100 x = 100 - z ...(i)
Again, z = 5y ...(ii)
and y + (z - x) = x + 8 y + z = 2x + 8.
Putting the value of x from equation (i) we get,
y + z = 2 (100 - z) + 8 y + 3z = 208. Putting the value of z from equation (ii) we get,
y + 3(5y) = 208 = 16y = 208. y = 13, from equation (ii), z = 65 and from (i) x = 35.
After 10 years, age of Ram's father = 65 + 10 = 75 years. Ans.(3)
Detailed Analysis:
The set of students who like Sunita and Ragini are disjoint sets.
Hence, the Venn diagram can be drawn as follows

There are 500 students in all.
From statement (2)
Sunita = 200. Hence, Ragini = 300.
From statement (1) A (Sunita) + A (Ragini) = 250 and B (Sunita) + B (Ragini) = 250.
From (2), A (Sunita) = 160. Hence, A (Ragini) = 90.
From (4), B (Sunita) = 20 % of 250 = 50. Hence, B (Ragini) = 200.
From (6), g (Sunita) = 50 and hence, b (Sunita) = 0 and a (Sunita) = 110. Hence, n (Sunita) = 40.
From (7), n (Ragini) = 60
It is given that 250 support B, hence the other 250 do not support B.
From (5), (a + n) of Ragini = 40 % of 250 = 100. Hence, a (Ragini) = 40.
Thus, the final solution is as follows.

Detailed Analysis:
The set of students who like Sunita and Ragini are disjoint sets.
Hence, the Venn diagram can be drawn as follows

There are 500 students in all.
From statement (2)
Sunita = 200. Hence, Ragini = 300.
From statement (1) A (Sunita) + A (Ragini) = 250 and B (Sunita) + B (Ragini) = 250.
From (2), A (Sunita) = 160. Hence, A (Ragini) = 90.
From (4), B (Sunita) = 20 % of 250 = 50. Hence, B (Ragini) = 200.
From (6), g (Sunita) = 50 and hence, b (Sunita) = 0 and a (Sunita) = 110. Hence, n (Sunita) = 40.
From (7), n (Ragini) = 60
It is given that 250 support B, hence the other 250 do not support B.
From (5), (a + n) of Ragini = 40 % of 250 = 100. Hence, a (Ragini) = 40.
Thus, the final solution is as follows.
